Let the required equation of a line be y =mx+c where m is any slope.
If this line passes through (x1,y1) then ,
y-y1=m(x-x1)
(y- -8) = m(x-2) as (x1,y1)=(2,-8). Or
y+8=m(x-2). Or
y=mx-2m+8 defines any straight line through (2,-8) for an desired slope.
Special cases when m is infinite:
If m is infinite, then 1/m = 0, then y/m=0 = x-2 or x-2 = 0 is a perpendicular line to x axis which passes through (2,-8)
Special case when m is zero:
If m= o, y=-8 is parallel to x axis.
Hope this helps.
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