A hockey puck on a frozen pond has an initial speed 18.50 m/s, it stops after sliding a distance of 224.1 m. If the coefficient of kinetic friction between the puck and the the ice surface is K, the frictional force acting on it is N*K where N is the normal force equal to M*g, M being the mass of the puck and g the acceleration due to gravity.
The deceleration due to the frictional force is K*g. The puck travels 224.1 m before stopping, use the formula v^2 - u^2 = 2*a*s.
18.5^2 - 0 = 2*K*g*224.1
As the gravitational acceleration is 9.8 m/s^2
18.5^2 = 2*K*9.8*224.1
=> K = 0.0779
The coefficient of kinetic friction between the puck the ice is 0.0779
No comments:
Post a Comment