Friday, January 21, 2011

How do you solve simultaneous equations using the substitution method ?x=y 6x-2y=10 x=-y 3x-6y=36

Substitution Method is used to solve simultaneous equations, as given above. To solve simultaneous equations the following steps should be taken:


Label the equations as i and ii,


x=y         ------(i)   


6x-2y=10 ------(ii)


The next step is to isolate one variable from any equation, which has been done already as x=y.


After this step input the value of x in eq(ii) and solve to get the value of y:


6x-2y=10 ------(ii)


6y-2y=10


4y=10


4y/4=10/4         divide both sides by 4


y=2.5


After this we would have to input this value in equation ii, but since it has already been determined that x=y we can say that x=2.5 as well.


x=2.5


y=2.5


To further check the answers input both values in eq(ii)


6x-2y=10


6(2.5)-2(2.5)=10


15-5=10


10=10


LHS=RHS proved.


The same steps are to be followed in this one:


x=-y         -------(i)  


3x-6y=36  -------(ii)



Input the value of x in eq(ii)


3x-6y=36


3(-y)-6y=36


-3y-6y=36


-9y=36


-9y/-9=36/-9        divide both sides by -9


y=-4


Now since both value are equal only their signs are different i.e. x=-y therefore x=4


Input both value in eq(ii) to check if they are correct:


3x-6y=36  -------(ii)


3(4)-6(-4)=36


12+24=36


36=36


LHS=RHS proved.

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