Verify: (cosx/1 + sinx) + (cosx/1-sinx) = 2secx

The brackets in the problem should be edited as below:

cosx/(1+sinx) + cosx/(1-sinx) = secx.

Solution:

We use sin^2x+cos^2x = 1. Or 1-sin^2x = cos^2x.

LHS: The commmon denominator is the LCM, (1+sinx)(1-sinx) = 1-sin^2x =  as (a+b)(a-b) = a^2-b^2. So, the LHS is,

cosx{(1-sinx) + 1+sinx}/ (1-sin^2x)

=cosx{2}/cos^2x = 2/cosx = 2secx  which is RHS.