What is the final temperature of this reaction ?150.0 mL of 0.50 M HCl is added to 50.0 mL of 1.00 M NaOH to make 200.0 g of solution. Other data...

Given

Mass of solution (m) = 200g

Initial Temp. of Solution (T1) = 42.3 degrees C + 273 = 315.3 K

Specific heat capacity of solution (Cp) = 4.184 J/g degrees C

Enthalpy change for neutralization (Q)  = 56 kj/mol = 56000 j/mol

Final Temp. of solution (T2) = ?

Formula...

Q = m * Cp (T2 - T1)

56000 = 200 (T2 - 315.3)

56000 = 200T2 - 63060

56000 + 63060 = 200T2

119060 = 200 T2

T2 = 119060/200

T2 = 595.3 K

The final temperature of reaction is 595.3 K.